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Q1. - (Topic 3) 

What does administrative distance refer to? 

A. the cost of a link between two neighboring routers 

B. the advertised cost to reach a network 

C. the cost to reach a network that is administratively set 

D. a measure of the trustworthiness of a routing information source 

Answer:

Reference: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080094195.shtml 

Administrative distance is the feature that routers use in order to select the best path when there are two or more different routes to the same destination from two different routing protocols. Administrative distance defines the reliability of a routing protocol. Each routing protocol is prioritized in order of most to least reliable (believable) with the help of an administrative distance value. 

Administrative distance is the first criterion that a router uses to determine which routing protocol to use if two protocols provide route information for the same destination. Administrative distance is a measure of the trustworthiness of the source of the routing information. The smaller the administrative distance value, the more reliable the protocol. 


Q2. - (Topic 2) 

Refer to the exhibit. 

What two things can the technician determine by successfully pinging from this computer to the IP address 172.16.236.1? (Choose two) 

A. The network card on the computer is functioning correctly. 

B. The default static route on the gateway router is correctly configured. 

C. The correct default gateway IP address is configured on the computer. 

D. The device with the IP address 172.16.236.1 is reachable over the network. 

E. The default gateway at 172.16.236.1 is able to forward packets to the internet. 

Answer: A,D 

Explanation: 

The source and destination addresses are on the same network therefore, a default gateway is not necessary for communication between these two addresses. 


Q3. - (Topic 5) 

Refer to the exhibit. 

After configuring two interfaces on the HQ router, the network administrator notices an error message. What must be done to fix this error? 

A. The serial interface must be configured first. 

B. The serial interface must use the address 192.168.1.2 

C. The subnet mask of the serial interface should be changed to 255.255.255.0 

D. The subnet mask of the FastEthernet interface should be changed to 255.255.255.240 

E. The address of the FastEthernet interface should be changed to 192.168.1.66 

Answer:

Explanation: 

The IP address 192.168.1.17 255.255.255.0 specifies that the address is part of the 192.168.1.0/24 subnet 

24 mask bits = 255.255.255.0 28 mask bits = 255.255.255.240 192.168.1.0/24 subnet has a host range of 192.168.1.1 to 192.168.1.254 (0 being network and 255 being broadcoast) 192.168.1.17/28 subnet has a host range of 192.168.1.17 to 192.168.1.30 (16 being network and 31 being broadcast) 192.168.1.65/28 subnet has a host range of 192.168.1.65 - 192.168.1.78 (64 being network and 79 being broadcast) 

if fa0/0 was left as /24, you can see that the host range includes the host range of 192.168.1.64/28 which conflicts. Simply speaking, you can't overlap the subnets. By changing the subnet mask of fa0/0 to 255.255.255.240, these networks would no longer overlap. 


Q4. - (Topic 1) 

Refer to the exhibit. 

The exhibit is showing the topology and the MAC address table. Host A sends a data frame to host D. What will the switch do when it receives the frame from host A? 

A. The switch will add the source address and port to the MAC address table and forward the frame to host D. 

B. The switch will discard the frame and send an error message back to host A. 

C. The switch will flood the frame out of all ports except for port Fa0/3. 

D. The switch will add the destination address of the frame to the MAC address table and forward the frame to host D. 

Answer:

Explanation: 

When switch receives the data frame from the host not having the MAC address already on the MAC table, it will add the MAC address to source port on MAC address table and sends the data frame. 


Q5. - (Topic 1) 

Which OSI layer header contains the address of a destination host that is on another network? 

A. application 

B. session 

C. transport 

D. network 

E. data link 

F. physical 

Answer:

Explanation: 

Only network address contains this information. To transmit the packets the sender uses network address and datalink address. But the layer 2 address represents just the address of the next hop device on the way to the sender. It is changed on each hop. Network address remains the same. 


Q6. - (Topic 4) 

Refer to the exhibit. 

A company wants to use NAT in the network shown. Which commands will apply the NAT configuration to the proper interfaces? (Choose two.) 

A. R1(config)# interface serial0/1 R1(config-if)# ip nat inside 

B. R1(config)# interface serial0/1 R1(config-if)# ip nat outside 

C. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat inside 

D. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat outside 

E. R1(config)# interface serial0/1 R1(config-if)# ip nat outside source pool 200.2.2.18 255.255.255.252 

F. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat inside source 10.10.0.0 255.255.255.0 

Answer: B,C 

Explanation: 

For NAT, you need to define which interfaces are inside and which are outside. The outside interface is the one that connects to the external network, and the one that will be used for translating addresses. The inside interface is for the internal network, and defines the network IP addresses that will get translated to the one specified in the outside network. 


Q7. - (Topic 2) 

A switch has 48 ports and 4 VLANs. How many collision and broadcast domains exist on the switch (collision, broadcast)? 

A. 4, 48 

B. 48, 4 

C. 48, 1 

D. 1, 48 

E. 4, 1 

Answer:

Explanation: 

A switch uses a separate collision domain for each port, and each VLAN is a separate broadcast domain. 

Topic 3, Routing Fundamentals 


Q8. - (Topic 1) 

Refer to the exhibit. 

What kind of cable should be used to make each connection that is identified by the numbers shown? 

A. 1 - Ethernet Crossover cable 2 - Ethernet straight-through cable 3 - Fiber Optic cable 4 - Rollover cable 

B. 1 - Ethernet straight-through cable 2 - Ethernet straight-through cable 3 - Serial cable 4 - Rollover cable 

C. 1 - Ethernet rollover cable 2 - Ethernet crossover cable 3 - Serial cable 4 - Null-modem cable 

D. 1 - Ethernet straight-through cable 2 - Ethernet Crossover cable 3 - Serial cable 4 - Rollover cable 

E. 1 - Ethernet straight-through cable 2 - Ethernet Crossover cable 3 - Serial cable 4 - Ethernet Straight-through cable 

Answer:

Explanation: 

When connecting a PC to a switch, a standard Ethernet straight through cable should be used. This same cable should also be used for switch to router connections. Generally 

speaking, crossover cables are only needed when connecting two like devices (PC-PC, 

switch-switch, router-router, etc). 

Routers connect to frame relay and other WAN networks using serial cables. 

Rollover cables are special cables used for connecting to the console ports of Cisco 

devices. 


Q9. - (Topic 5) 

Refer to the exhibit. 

A technician pastes the configurations in the exhibit into the two new routers shown. Otherwise, the routers are configured with their default configurations. 

A ping from Host1 to Host 2 fails, but the technician is able to ping the S0/0 interface of R2 from Host 1. The configurations of the hosts have been verified as correct. What could be the cause of the problem? 

A. The serial cable on R1 needs to be replaced. 

B. The interfaces on R2 are not configured properly 

C. R1 has no route to the 192.168.1.128 network. 

D. The IP addressing scheme has overlapping subnetworks. 

E. The ip subnet-zero command must be configured on both routers. 

Answer:

Explanation: 

Without a static route pointing to the host 2 network the router R1 is unaware of the path to take to reach that network and reply traffic cannot be sent. 


Q10. - (Topic 3) 

Which IP addresses are valid for hosts belonging to the 10.1.160.0/20 subnet? (Choose three.) 

A. 10.1.168.0 

B. 10.1.176.1 

C. 10.1.174.255 

D. 10.1.160.255 

E. 10.1.160.0 

F. 10.1.175.255 

Answer: A,C,D 

Explanation: 

All IP address in IP ranges between: 10.1.160.1 and 10.1.175.254 are valid as shown below Address: 10.1.160.0 00001010.00000001.1010 0000.00000000 Netmask: 255.255.240.0 = 20 11111111.11111111.1111 0000.00000000 Wildcard: 0.0.15.255 00000000.00000000.0000 1111.11111111 

Which implies that: Network: 10.1.160.0/20 00001010.00000001.1010 0000.00000000 HostMin: 10.1.160.1 00001010.00000001.1010 0000.00000001 HostMax: 10.1.175.254 00001010.00000001.1010 1111.11111110 Broadcast: 10.1.175.255 00001010.00000001.1010 1111.11111111